The right order of increase in the ionic character of the molecules
 LiF, K₂O, N₂, SO₂, ClF₃ is :

1. N₂ < SO₂ < ClF₃ < K₂O < LiF

2. N₂ > SO₂ > ClF₃ > K₂O < LiF

3. N₂ > SO₂ > K₂O > ClF₃ > LiF

4. LiF > K₂O < ClF₃ > SO₂ > N₂

The shape of  AsF₅ is:
1. Pentagonal bipyramidal.
2. Trigonal bipyramidal.
3. Distorted tetrahedral.
4. Square pyramidal.

The incorrect statement about NH₃ and H₂O is :

1. The bond angle in NH₃ is less than in H₂O.

2. Both have distorted tetrahedral geometries.

3. The bond angle in H₂O is less than in NH₃.

4. Both are sp³ hybridized. 

The relative order of stability of the following species: \(\mathrm{O}_2,\mathrm{O}^+_2,\mathrm{O}^-_2~\mathrm{and}~\mathrm{O}^{2-}_2\) is -

The plus and negative sign of the orbitals mean:

1. Wave function.

2. Probability density.

3. Quantum number of orbitals.

4. Frequency of orbitals.

In the option are given sequences of increasing bond order for the following species. The correct option is :
\(\mathrm{O}_2,\mathrm{N}_2,\mathrm{O}^+_2 ~\mathrm{and}~\mathrm{O}^-_2\)  

${\mathrm{AlCl}}_3$ $+$ ${\mathrm{Cl}}^{-}$ $\to$ ${\mathrm{AlCl}}_4^{-}$

The change in the hybridization of the Al atom in the above reaction is:
1. \(s p^{2} \text { to } s p^{3}\)
2. \(\mathrm{sp}^{3} \text { to } s p^{2}\)
3. \(\mathrm{sp}^{3} \text { to } \mathrm{dsp}{ }^{2}\)
4. \(\operatorname{sp}^{2} \text { to } d s p^{2}\)

Considering the X-axis as the internuclear axis, a sigma bond will not be formed in:

$1.$ $1\mathrm{s}$ $\mathrm{and}$ $2\mathrm{s}$
$2.$ $1\mathrm{s}$ $\mathrm{and}$ $2{\mathrm{p}}_{\mathrm{x}}$
$3.$ $2{\mathrm{p}}_{\mathrm{y}}$ $\mathrm{and}$ $2{\mathrm{p}}_{\mathrm{y}}$
$4.$ $1\mathrm{s}$ $\mathrm{and}$ $1\mathrm{s}$

The driving force of an atom to form chemical bonds involves:
1. To increase the size.
2. To decrease size.
3. To attain stability.
4. None of the above.

The Lewis dot symbols for atoms of the elements Mg, Na, O, and N, respectively, would be:

1.
2.
3.
4.