Electron Affinity (EA) Past Year (2006 - 2015) MCQs Classification of Elements and Periodicity in Properties Chemistry NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers

The formation of the oxide ion O^2– (g), from the oxygen atom requires first an exothermic and then an endothermic step as shown below,
$O (g) + e^{-} \to O^{-};$ $∆_{f} H^{0} = - 141$ $kJ$ ${mol}^{- 1}$
$O^{-} (g) + e^{-} \to O^{2 -} (g);$ $∆_{f} H^{0} = + 780$ $kJ$ ${mol}^{- 1}$

Thus, the process of formation of O^2– in the gas phase is unfavorable even though O^2– is isoelectronic with neon. It is due to the fact that:

1.	Electron repulsion outweighs the stability gained by achieving noble gas configuration.
2.	O^– ion has a comparatively smaller size than the oxygen atom.
3.	Oxygen is more electronegative.
4.	Addition of electrons in oxygen results in a large size of the ion.

Subtopic: Electron Affinity (EA) |

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The correct order of least negative to most negative electron gain enthalpy for C, Ca, Al, F and O is:

1. Al < Ca < O < C < F
2. Al < O < C < Ca < F
3. C < F < O < Al < Ca
4. Ca < Al < C < O < F

Subtopic: Electron Affinity (EA) |

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The value of electron gain enthalpy of Na⁺, if IE₁ of Na = 5.1 eV, is:

1. +10.2 eV

2. –5.1 eV

3. –10.2 eV

4. +2.55 eV

Subtopic: Electron Affinity (EA) |

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The correct order of increasing electron affinity for the elements, O, S, F and Cl is:

1.	Cl < F < O < S	2.	O < S < F < Cl
3.	F < S < O < Cl	4.	S < O < Cl < F

Subtopic: Electron Affinity (EA) |

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Which one of the following arrangements does not give the correct picture of the trends indicated against it?
1. F₂> Cl₂> Br₂> I₂ : Oxidising power
2. F<Cl>Br>I : Electron gain enthalpy
3. F₂> Cl₂> Br₂> I₂ : Bond dissociation energy
4. F> Cl > Br > I : Electronegativity

Subtopic: Ionization Energy (IE) | Electronegativity | Electron Affinity (EA) |

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