The radius of a hydrogen shell is 0.53Å. In its first excited state, radius of the shell will be:
1. 2.12 Å
2. 1.06 Å
3. 8.5 Å
4. 4.24 Å

Ionization energy of second orbit of $L{i}^{+2}$ will be:
1.  122.4 eV
2.  40.8 eV
3.  30.6 eV
4.  13.6 eV

In the Hydrogen atom, the energy of the first excited state is – 3.4 eV. Then find out K.E(kinetic energy) of the same orbit of the Hydrogen atom:

1. + 3.4 eV

2. + 6.8 eV

3. – 13.6 eV

4. + 13.6 eV

If the energy of the second Bohr orbit of the hydrogen atom is –328 kJ mol^–1, the energy of the fourth Bohr orbit would be: