Percentage of C, H & N of a compound is given as follows:
C=40%, H=13.33%, N=46.67%
The empirical formula of the compound will be:

1. CH2N

2. C2H4N

3. CH4N

4. CH3N

Subtopic:  Empirical & Molecular Formula |
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A compound contains C, H, and O. If C = 40% and H = 6.67% and rest is oxygen, then the empirical formula of the compound will be:

1. CH2O

2. CH4O

3. CH4O2

4. CHO

Subtopic:  Empirical & Molecular Formula |
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The percentages of C, H, and N in an organic compound are 40%, 13.3%, and 46.7% respectively.
The empirical formula of the compound is:

1. C3H13N3 2. CH2N
3. CH4N 4. CH6N
Subtopic:  Empirical & Molecular Formula |
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