Concentration Based Problem Recommended PYQs (STRICTLY NCERT Based) Some Basic Concepts Of Chemistry Chemistry NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers

The amount of glucose required to prepare 250 mL of $\dfrac{M}{20}$ aqueous solution is:
(Molar mass of glucose: 180 g $\mathrm{mol ^{-1}}$)
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g

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Mass of glucose $\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)$ required to be dissolved to prepare one litre of its solution which is isotone with $15~g~L^{-1}$solution of urea $\mathrm{(NH_2 CONH_2)}$ is:

(Given : Molar mass in g $\mathrm{mol}^{-1}$ C:12, H:1, O: 16, N:14 )

1. 55 g
2. 15 g
3. 30 g
4. 45 g

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The density of 1 M solution of a compound 'X' is 1.25 g mL^–1. The correct option for the molality of solution is:
(Molar mass of compound X = 85 g):

1.	0.705 m	2.	1.208 m
3.	1.165 m	4.	0.858 m

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The density of a 2 M aqueous solution of NaOH is 1.28 g/ $c m^{3}$ . The molality of the solution is:
[molecular mass of NaOH = 40 $g m o l^{- 1}$ ]

1.	1.20 m	2.	1.56 m
3.	1.67 m	4.	1.32 m

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Which of the following is dependent on temperature?

1.	Molarity	2.	Mole fraction
3.	Weight percentage	4.	Molality

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Calculate the mole fraction of the solute in a 1.00 m aqueous solution.

1.	0.177	2.	0.771
3.	0.0534	4.	0.0177

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The weight of 70 % HNO₃concentrated nitric acid solution that should be used to prepare 250 mL of 2.0 M HNO₃ is:
1. 90.0 g conc. HNO₃
2. 70.0 g conc. HNO₃
3. 54.0 g conc. HNO₃
4. 45.0 g conc. HNO₃

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6.02 × 10²⁰ molecules of urea are present in 100 mL of its solution. The concentration of the solution is:
1. 0.01 M
2. 0.001 M
3. 0.1 M
4. 0.02 M

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Mole fraction of solute in a 1.00 molal aqueous solution is:
1. 0.0177
2. 0.0344
3. 1.770
4. 0.1770

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25.3 g of sodium carbonate, Na₂CO₃, is dissolved in enough water to make 250 mL of a solution. If sodium carbonate completely dissociates, the molar concentrations of sodium ion, Na⁺ and carbonate ion, $C O_{3}^{2 -}$ are respectively:
(molar mass of Na₂CO₃ = 106g mol^-1)

1. 0.955 M and 1.910 M
2. 1.910 M and 0.955 M
3. 1.90 M and 1.910 M
4. 0.477 M and 0.477 M

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