Two particles are in SHM in a straight line. Amplitude A and time period T of both the particles are equal. At time t = 0, one particle is at displacement Y1 = + A and the other at Y2 = -A/2, and they are approaching towards each other. After what time they cross each other?
1. T/3
2. T/4
3. 5T/6
4. T/6
Two particles execute SHM of the same amplitude of \(20\) cm with the same time period along the same line about the same equilibrium position. The maximum distance between the two is \(20\) cm. Their phase difference in radians is:
1. \(\frac{2\pi}{3}\)
2. \(\frac{\pi}{2}\)
3. \(\frac{\pi}{3}\)
4. \(\frac{\pi}{4}\)
Two particles \(P\) and \(Q\) execute simple harmonic motion with the same amplitude and time period along the same straight line about a common equilibrium position \(O.\) When they are on opposite sides of \(O,\) at equal distances from it, they move in the same direction with a speed of \(1.2\) m/s At another instant, when their displacements from \(O\) are equal, they move in opposite directions with a speed of \(1.6\) m/s. What is the maximum speed of either particle?
1. \(2.8\)
2. \(2.5\)
3. \(3\)
4. \(2\)
The time period of a particle executing SHM is 8 sec. At t = 0 it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is :
1.
2.
3.
4.
The displacement of a body executing SHM is given by x= A sin (2t + /3). The first time from t = 0 when the velocity is maximum is :
1. 0.33 sec
2. 0.16 sec
3. 0.25 sec
4. 0.5 sec
A body performs S.H.M. . Its kinetic energy K varies with time t as indicated by graph
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2. | ![]() |
| 3. | ![]() |
4. | ![]() |
The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is

1. 1 102 N/m
2. 150 N/m
3. 0.667 102 N/m
4. 3 102 N/m
The velocity-time diagram of a harmonic oscillator is shown in the adjoining figure. The frequency of oscillation is

1. 25 Hz
2. 50 Hz
3. 12.25 Hz
4. 33.3 Hz
For a particle executing SHM the displacement \(x \) is given by, \(A\cos \omega t.\) Identify the graph which represents the variation of potential energy (P.E.) as a function of time \(t\) and displacement \(x.\)

1. I, III
2. II, IV
3. II, III
4. I, IV
The graph shows the variation of displacement of a particle executing SHM with time. We infer from this graph that:

| 1. | the force is zero at the time \(T/8\). |
| 2. | the velocity is maximum at the time \(T/4\). |
| 3. | the acceleration is maximum at the time \(T\). |
| 4. | the P.E. is equal to the total energy at the time \(T/4\). |