Fg and Fe represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of Fg/ Fe is of the order of
(1) 1042
(2) 10
(3) 1
(4) 10–43
Four charges are arranged at the corners of a square \(ABCD,\) as shown in the adjoining figure. The force on the positive charge \(Q\) kept at the centre \(O\) is:
1. | Zero | 2. | Along the diagonal \(AC\) |
3. | Along the diagonal \(BD\) | 4. | Perpendicular to side \(AB\) |
In the absence of other conductors, the surface charge density
(1) Is proportional to the charge on the conductor and its surface area
(2) Inversely proportional to the charge and directly proportional to the surface area
(3) Directly proportional to the charge and inversely proportional to the surface area
(4) Inversely proportional to the charge and the surface area
Out of gravitational, electromagnetic, Vander Waals, electrostatic and nuclear forces; which two are able to provide an attractive force between two neutrons
(1) Electrostatic and gravitational
(2) Electrostatic and nuclear
(3) Gravitational and nuclear
(4) Some other forces like Vander Waals
Three charges \(4q,Q,\) and \(q\) are in a straight line in the position of \(0,l/2,\) and \(l\) respectively. The resultant force on \(q\) will be zero if \(Q\) equal to:
1. \(-q\)
2. \(-2q\)
3. \(\frac{-q}{2}\)
4. \(4q\)
Two small spheres each having the charge \(+Q\) are suspended by insulating threads of length \(L\) from a hook. If this arrangement is taken in space where there is no gravitational effect, then the angle between the two suspensions and the tension in each will be:
1. \(180^\circ,\) \(\frac{1}{4 \pi \epsilon_{0}} \frac{Q^{2}}{(2 L )^{2}}\)
2. \(90^\circ,\) \(\frac{1}{4 \pi \epsilon_{0}} \frac{Q^{2}}{(L )^{2}}\)
3. \(180^\circ,\) \(\frac{1}{4 \pi \epsilon_{0}} \frac{Q^{2}}{2 L ^{2}}\)
4. \(180^\circ,\) \(\frac{1}{4 \pi \epsilon_{0}} \frac{Q^{2}}{ L ^{2}}\)
Two charges each of 1 coulomb are at a distance 1 km apart, the force between them is
(1) 9 × 103 Newton
(2) 9 × 10–3 Newton
(3) 1.1 × 10–4 Newton
(4) 104 Newton
Two charges \(+2\) C and \(+6\) C are repelling each other with a force of \(12\) N. If each charge is given \(-2\) C of charge, then the value of the force will be:
1. | \(4\) N (attractive) | 2. | \(4\) N (repulsive) |
3. | \(8\) N (repulsive) | 4. | zero |
The dielectric constant of pure water is 81. Its permittivity will be:
1. 7.12 × 10–10 MKS units
2. 8.86 × 10–12 MKS units
3. 1.02 × 1013 MKS units
4. Cannot be calculated
Force of attraction between two point charges Q and – Q separated by d meter is Fe. When these charges are given to two identical spheres of radius R = 0.3 d whose centres are d meter apart, the force of attraction between them is
1. Greater than Fe
2. Equal to Fe
3. Less than Fe
4. None of the above