can be differentiated by:

1. Hinsberg test                 

2. Iso-cyanide test

3. NaNO2, HCl, then β-Naphthol     

4. NaOH

Subtopic:  Aromatic Conversion |
 62%
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(p-ethyl phenol) (p-methyl anisole) (p-ethyl benzyl alcohol)

Above compounds can be differentiated by using the reagent:-

(a) NaOH, Tollen's reagent, FeCl3

(b) CrO3, Tollen's reagent, FeCl3,

(c) Tollen's reagent, CrO3, FeCl3

(d) Na, Tollen's reagent, FeCl3

 

 

Subtopic:  Aromatic Conversion |
 53%
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Give test to differentiate (Bromobenzene) Ph-Br and benzyl bromide (PhCH2Br).
(1) (i) aq. KOH (ii) Na

(2) AgNO3

(3) KMnO4

(4) All these

Subtopic:  Aromatic Conversion |
 75%
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Give test to differentiate 1,1-dichloroethane and 1, 2-dichloroethane:
1. 2,4-DNP then aq. KOH

2. Aq. KOH then 2, 4-DNP

3. NaHSO3

4. Lucas reagent

Subtopic:  conversion chart for n to n carbon |
 66%
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In the dehydration reaction,
    CH3CONH2P2O5CH3CN,
the hybridization state of carbon changes from:

(1) sp3 to sp2

(2) sp to sp

(3) sp2 to sp

(4) sp to sp3

Subtopic:  conversion chart for n to n carbon |
 85%
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The reagent used in dehydrohalogenation process is:

1. Alcoholic KOH

2. NaNH2

3. C2H5ONa

4. All of these

Subtopic:  conversion chart for n to n carbon |
 75%
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The reaction, CH2=CHCHOHXgives:

1. CH3CHXCHO

2. CH2XCHCHO

3. CH2=CHCHX2

4. None of these

Subtopic:  Differentiation of Organic Compound |
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The reagent used in dehalogenation process is:

1. KOH alc.

2. Zn dust+ alc.

3. Na

4. KOH(aq)

Subtopic:  conversion chart for n to n carbon |
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An unknown compound A has a molecular formula C4H6. When A is treated with excess of Br2 a new substance B with formula C4H6Br4 is formed. A forms a white ppt. with ammoniacal silver nitrate solution. A may be-

1. But-1-yne

2. But-2-yne

3. But-1-ene

4. But-2-ene

Subtopic:  Differentiation of Organic Compound |
 63%
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The appropriate reagent for the following transformation,

  is :

1. Zn(Hg),HCl

2. NH2NH2, OH-

3. H2/Ni

4. NaBH4

Subtopic:  Differentiation of Organic Compound |
 62%
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