The correct order of Cl-O bond order is

$1. {\mathrm{ClO}}_3^{-} < {\mathrm{ClO}}_4^{-} < {\mathrm{ClO}}_2^{-} < {\mathrm{ClO}}^{-}$
$2. {\mathrm{ClO}}^{-} < {\mathrm{ClO}}_4^{-} < {\mathrm{ClO}}_3^{-} < {\mathrm{ClO}}_2^{-}$
$3. {\mathrm{ClO}}^{-} < {\mathrm{ClO}}_2^{-} < {\mathrm{ClO}}_3^{-}< {\mathrm{ClO}}_4^{-}$
$4. {\mathrm{ClO}}_4^{-} < {\mathrm{ClO}}_3^{-} < {\mathrm{ClO}}_2^{-} < {\mathrm{ClO}}^{-}$

0.01 mole of ${\mathrm{H}}_3{\mathrm{PO}}_{\mathrm{x}}$ is completely neutralized by 0.56 gram of KOH hence :

1. x = 3 and given acid is dibasic

2. x = 2 and given acid is monobasic

3. x = 3 and given acid is monobasic

4. x = 4 and given acid forms three series of salt

The shape of ${\mathrm{XeF}}_3^{+}$ is :

1. Trigonal planar

2. Pyramidal

3. Bent T-shape

4. See-saw

Which is the following pairs of species have identical shapes ?

$1. {\mathrm{NO}}_2^{+} \mathrm{and} {\mathrm{NO}}_2^{-}$
$2. {\mathrm{PCI}}_5 \mathrm{and} {\mathrm{BrF}}_5$
$3. {\mathrm{XeF}}_4 \mathrm{and} {\mathrm{ICI}}_4^{-}$
$4. {\mathrm{TeCl}}_4 \mathrm{and} {\mathrm{XeO}}_4$

Which of the following leads to bonding orbital?

1.
2.
3.
4.

Which of the following overlap is incorrect (assuming Z-axis is internuclear axis) ?

(A) $2{\mathrm{p}}_{\mathrm{y}} + 2{\mathrm{p}}_{\mathrm{y}} \to \mathrm{\pi }$ - Bond formation

(B) $2{\mathrm{p}}_{\mathrm{x}} + 2{\mathrm{p}}_{\mathrm{x}} \to \mathrm{\sigma }$ - Bond formation

(C) $3{\mathrm{d}}_{\mathrm{xy}} + 3{\mathrm{dp}}_{\mathrm{xy}} \to \mathrm{\pi }$ - Bond formation

(D) $2\mathrm{s} + 2{\mathrm{p}}_{\mathrm{y} }\to \mathrm{\pi }$ - Bond formation

(E) $3{\mathrm{d}}_{\mathrm{xy}} + 3{\mathrm{d}}_{\mathrm{xy}} \to \mathrm{\delta }$ - Bond formation

(F) $2{\mathrm{p}}_{\mathrm{z}} + 2{\mathrm{p}}_{\mathrm{z}} \to \mathrm{\sigma }$ - Bond formation

1. A, B, C

2. C, F

3. B, E

4. B, C, D

Which of the following is not present in ${\mathrm{XeO}}_3$ molecule ?

$1. {\mathrm{sp}}^3 + {\mathrm{p}}_{\mathrm{x}}$
$2. {\mathrm{sp}}^3 + {\mathrm{p}}_{\mathrm{y}}$
$3. {\mathrm{d}}_{\mathrm{xz}} +\hspace{0.17em}{\mathrm{p}}_{\mathrm{x}}$
$4. {\mathrm{sp}}^3 +\hspace{0.17em}\mathrm{s}$

The incorrect order of lattice energy is :

$1. {\mathrm{AIF}}_3 > {\mathrm{MgF}}_2$
$2. {\mathrm{Li}}_3\mathrm{N} > {\mathrm{Li}}_2\mathrm{O}$
$3. \mathrm{NaCl} > \mathrm{LiF}$
$4. \mathrm{TiC} > \mathrm{ScN}$

The bond angles of  NH₃, NH₄⁺ and NH₂^-  are in the order :

1. NH₂^- > NH₃ > NH₄⁺

2. ${\mathrm{NH}}_4^{+}>{\mathrm{NH}}_3>{\mathrm{NH}}_2^{-}$

3. ${\mathrm{NH}}_3>{\mathrm{NH}}_2^{-}>{\mathrm{NH}}_4^{+}$

4. ${\mathrm{NH}}_3>{\mathrm{NH}}_4^{+}>{\mathrm{NH}}_2^{-}$

The "O-N-O" bond angle is maximum in 

1. ${\mathrm{N}}_2\mathrm{O}$

2. ${\mathrm{NO}}_2^{+}$

3. ${\mathrm{NO}}_2^{-}$

4. ${\mathrm{NO}}_3^{-}$