The total energy of a particle, executing simple harmonic motion is:
1.
2.
3. Independent of x
4.
A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by , where is equal to
(1) g
(2) g-a
(3) g+a
(4)
If the length of second's pendulum is decreased by 2%, how many seconds it will lose per day?
1. 3927 sec
2. 3727 sec
3. 3427 sec
4. 864 sec
In a simple pendulum, the period of oscillation T is related to length of the pendulum l as
(1) =constant
(2) =constant
(3) =constant
(4) =constant
The equation of motion of a particle is \({d^2y \over dt^2}+Ky=0 \) where \(K\) is a positive constant. The time period of the motion is given by:
1. | \(2 \pi \over K\) | 2. | \(2 \pi K\) |
3. | \(2 \pi \over \sqrt{K}\) | 4. | \(2 \pi \sqrt{K}\) |
The kinetic energy of a particle executing SHM is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation will be:
1.
2.
3.
4.
A pendulum has time period T. If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth then its time period on the other planet will be
(1)
(2) T
(3)
(4) T
A particle in SHM is described by the displacement equation position of the particle is 1 cm and its initial velocity is cm/s, what is its amplitude? (The angular frequency of the particle is )
(1) 1 cm
(2) cm
(3) 2 cm
(4) 2.5 cm
A simple pendulum hanging from the ceiling of a stationary lift has a time period T1. When the lift moves downward with constant velocity, the time period is T2, then
(1) is infinity
(2)
(3)
(4)
If the length of a pendulum is made 9 times and mass of the bob is made 4 times , then the value of time period becomes
(1) 3T
(2) 3/2T
(3) 4T
(4) 2T