Ncert Exercises & Solutions

Which of the following complexes show linkage isomerism?
(a) ${[Co {({NH}_{3})}_{5} ({NO}_{2})]}^{2 +}$
(b) $[Co {(H_{2} O)}_{5} CO]^{3 +}$
(c) $[Cr {({NH}_{3})}_{5} SCN]^{2 +}$
(d) ${[Fe {(en)}_{2} {Cl}_{2}]}^{+}$

Choose the correct option
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

Coordination compounds containing a ligand with more than one non-equivalent binding

Position (known as ambident ligand) show linkage isomerism

$[C o (N H]$ ₃)5(NO₂)+ contains NO $_{2}$ which have two donor sites N and © can be shown by

arrow (9) as

$[C r (N H]$ ₃)5SCN2+ contains SCN which have two different donor sites S and N can be shown by arrow ( $\to$ ) as

$\to S — C = N \leftarrow$

Hence, ${[C o (N H_{3}) (N O_{2}]}^{2 +} a n d [C r (N H]$ ₃)5SCN)2+ show linkage isomerism. While

${[C o (H_{2} O_{5} C O)]}^{3 +} a n d {[F e {(e n)}_{2} C l_{2}]}^{+}$ has no ambident ligand, So, these two will not show

linkage isomerisrn.

Hence, options (a) and (c) are correct choices.

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