Ncert Exercises & Solutions

A brown ring is formed in the ring test for ${NO}_{3}^{-}$ ion. It is due to the formation of:

1. [Fe(H₂O)₅(NO)]²⁺
2. FeSO₄.NO₂
3. [Fe(H₂O)₄ (NO)₂]²⁺
4. FeSO₄. HNO₃

Hint: The IUPAC name of the compound formed in brown ring is PentaaquanitrosylIron(I)Sulphate.

The brown ring complex compound is given as
[Fe(H₂O)₅NO]SO₄
The complex ion is [Fe(H₂O)₅NO]²⁺
Oxidation numbers of H₂O is zero and NO is +1
Oxidation state of Fe is +1.

The IUPAC name of the compound is PentaaquanitrosylIron(I ) Sulphate.

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