Ncert Exercises & Solutions

3.2 Given the standard electrode potentials,

K+/K = –2.93V, Ag+/Ag = 0.80V,

Hg2+/Hg = 0.79V

Mg2+/Mg = –2.37 V, Cr3+/Cr = – 0.74V

Arrange these metals in their increasing order of reducing power.

Hint: Lower is the reduction potential, higher will be reducing power.

The lower the reduction potential, the higher is the reducing power.

The given standard electrode potentials increase in the order of K⁺/K < Mg²⁺/Mg < Cr³⁺/Cr < Hg²⁺/Hg < Ag⁺/Ag.

Hence, the reducing power of the given metals increases in the following order: Ag < Hg < Cr < Mg < K

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