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7.62 A 0.02M solution of pyridinium hydrochloride has pH = 3.44. Calculate the ionization constant of pyridine.

pH = 3.44
We know that,
pH = -log [H+]
[H+]=3.63×10-4
Then, Kh=(3.63×10-4)20.02(concentration=0.02 M)
Kh=6.6×10-6
Now, Kh=KWKa
Ka=KwKh=10-146.6×10-6
        =1.51×10-9