Ncert Exercises & Solutions

7.6 For the following equilibrium, Kc= 6.3 × 1014 at 1000 K

$NO (g) + O_{3} (g) {NO}_{2} (g) + O_{2} (g)$

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

It is given that

K_{c}

for the forward reaction is

6.3 \times 10^{14} .

Then,

K_{c}

for the reverse reaction will be,

K'_{c} = \frac{1}{K_{c}}

= \frac{1}{6.3 \times 10^{14}}

= 1.59 \times 0^{- 15}