Ncert Exercises & Solutions

7.2 What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2]= 0.60M, [O2] = 0.82M and [SO3] = 1.90M ?

2SO2(g) + O2(g) 2SO3(g)

The equilibrium constant

(K_{c})

for the given reaction is:

K_{c} = \frac{{[{SO}_{3}]}^{2}}{{[{SO}_{2}]}^{2} [O_{2}]}

= \frac{{(1.90)}^{2} M^{2}}{{(0.60)}^{2} (0.821) M^{3}}

= 12.239 M^{- 1} (approximately)

Hence, K for the equilibrium is

12.239 M^{- 1}

.