Ncert Exercises & Solutions

1.0 mol of monoatomic ideal gas is expanded from state (1) to state (2) as shown in figure. Calculate the work done for the expansion of gas from state (1) to state (2) at 298 K.

The given diagram represent that the process is carried out in infinite steps, hence it is isothermal reversible expansion of the ideal gas from pressure 2.0 atm to 1.0 atm 298 K.

W = - 2.303 nRT \log \frac{p_{1}}{p_{2}}

W = - 2.303 \times 1 mol \times 8.314 {JK}^{- 1} {mol}^{- 1} \times 298 K \log 2 (∵ \frac{p_{1}}{p_{2}} = \frac{2}{1})

W = - 2.303 \times 1 \times 8.314 \times 298 \times 0.3010 J

W = - 1717.46 J

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