Ncert Exercises & Solutions

5.12 Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.
(R = 0.083 bar dm3 K–1 mol–1).

G i v e n,

n = 4.0 m o l V = 5 d m^{3} p = 3.32 b a r

R = 0.083 b a r d m^{3} K^{- 1} m o l^{- 1}

The temperature (T) can be calculated using the ideal gas equation as:

p V = n R T

\Rightarrow T = \frac{p V}{n R}

= \frac{3.32 \times 5}{4 \times 0.083} = 50 K

Hence, The requires temperature is 50 K.