Ncert Exercises & Solutions

Wavelengths of different radiations are given below.

$λ (A) = 300 nm$ $λ (B) = 300 μm$ $λ (C) = 3 nm$ $λ (D) = 30 Å$

Arrange the radiations in the increasing order of their energies.

λ (A) = 300 nm = 300 \times 10^{- 9} m

λ (B) = 300 μm = 300 \times 10^{- 6} m

λ (C) = 3 nm = 3 \times 10^{- 9} m

λ (D) = 30 Å = 30 \times 10^{- 10} m = 3 \times 10^{- 9} m

Energy,

E = \frac{hc}{λ}

Therefore,

E \propto \frac{1}{λ}

Increasing order of energy is B<A<C=D