Ncert Exercises & Solutions

The molarity of a solution containing 5.85 g of NaCl(s) per 500 mL of solution is:

1. 4 mol L^–1

2. 20 mol L^–1

3. 0.2 mol L^–1

4. 2 mol L^–1

Hint:

Molarity = \frac{weight \times 1000}{molecular weight \times volume (mL)}

Explanation:

Step:1

Molarity (M) determines the number of moles of solute per liter of solution which is denoted as moles/Liter and is amongst the most common units that are used for measuring the concentration of a solution.

Molarity = no. of moles of solute /volume of solution in liters

Step 2:

Since, Molarity (M) is calculated by the following equation is as follows:

Molarity = \frac{weight \times 1000}{molecular weight \times volume (mL)}

= \frac{5.85 \times 1000}{58.5 \times 500} = 0.2 mol L^{- 1}

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