3.12 A ball is dropped from a height of 90 m on a floor. At each collision with the floor, the ball loses one-tenth of its speed. Plot the speed-time graph of its motion between t = 0 to 12 s.
Taking vertical downward motion of ball from a height 90 m, we have
u=0, a=10 m/s2 ,h=90 m
t=√2ha=√2×9010=3√2 s=4.24 s
v=√2as=√2×10×90=30√2 m/s
Rebound velocity of ball,
u'=910v=910×30√2=27√2 m/s
Time to reach highest point ,t'=u'a=27√210=3.81 s
Total time=t+t'=4.24+3.81=8.05 s
The ball will take further 3.81 s to fall back to floor.
Velocity before striking the floor=27√2 m/s
Velocity of ball after striking the floor
=910×27√2=24.3√2 m/s
Total time elapsed before upward motion of ball=8.05+3.81=11.86 s
The speed-time graph of the ball is represented in the given figure as:
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