A girl riding a bicycle along a straight road with a speed of \(5\) m/s throws a stone of mass \(0.5\) kg which has a speed of \(15\) m/s with respect to the ground along her direction of motion. The mass of the girl and bicycle is \(50\) kg. What is the change in speed of the bicycle after the stone is thrown?
1.
\(0.1~\text{m/s}\)
2.
\(0.7~\text{m/s}\)
3.
\(1~\text{m/s}\)
4.
\(5~\text{m/s}\)
Hint: Use law of conservation of linear momentum
Step 1: Apply linear momentum conservation to calculate the speed of the bicycle after the stone is thrown.
Given, total mass of girl, bicycle and stone = (50 + 0.5) kg = 50.5 kg.
Velocity of bicycle, = 5 m/s, Mass of stone = 0.5 kg
Velocity of stone = 15 m/s, Mass of girl and bicycle m = 50 kg
Yes, the speed of the bicycle changes after the stone is thrown.
Let after throwing the stone the speed of the bicycle be v m/s.
According to law of conservation of linear momentum,
