Ncert Exercises & Solutions

11.1 The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.

The relation between Kelvin and Celsius's scales is given by:

$T_{C} = T_{K} - 273.15 \dots . (i)$

The relation between Celsius and Fahrenheit's scales is given by:

$T_{F} = \frac{9}{5} T_{C} + 32 . . . . (ii)$

For neon: $T_{K}$ = 24.57 K

$T_{C}$ = 24.57 – 273.15 = –248.58°C

$T_{F} = \frac{9}{5} T_{C} + 32$

$= \frac{9}{5} (- 248) + 32 = 415.44 ° F$

For carbon dioxide:

$T_{K}$ = 216.55 K

$∴$ $T_{C}$ = 216.55 – 273.15 = –56.60°C

$T_{F} = \frac{9}{5} T_{C} + 32 = \frac{9}{5} (- 56.60) + 32 = - 69.88 ° C$

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