A cubic vessel (with faces horizontal \(+\) vertical) contains an ideal gas at NTP. The vessel is being carried by a rocket which is moving at a speed of \(500~\text{ms}^{-1}\) in the vertical direction. The pressure of the gas inside the vessel as observed by us on the ground:
| 1. | remains the same because \(500~\text{ms}^{-1}\) is very much smaller than \(v_\text{rms}\) of the gas. |
| 2. | remains the same because the motion of the vessel as a whole does not affect the relative motion of the gas molecules and the walls. |
| 3. | will increase by a factor equal to \(\left(\dfrac{v_\text{rms}^2+(500)^2}{v_\text{rms}^2}\right) \) where \(v_\text{rms}^2\) was the original mean square velocity of the gas. |
| 4. | will be different on the top wall and bottom wall of the vessel. |
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