13.22 For the β+ (positron) emission from a nucleus, there is another competing process known as electron capture (electron from an inner orbit, say, the K–shell, is captured by the nucleus and a neutrino is emitted).

\(e^{+}+{ }_{Z}^{A} X \rightarrow {}_{z-1}^{A} Y+\nu\)

Show that if β+ emission is energetically allowed, electron capture is necessarily allowed but not vice–versa.

Hint: Q-value must be positive for an energetically-allowed nuclear reaction
Step 1: Find the nuclear reactions for β+ emission and electron capture.
Let the amount of energy released during the electron capture process be Q1. The nuclear reaction can be written as:
\(e^{+}+{ }_{Z}^{A} X \rightarrow{ }_{Z-1}^{A} Y+\nu+Q_{1}\)
Let the amount of energy released during the positron capture process be Q2. The nuclear reaction can be written as:
\({ }_{Z}^{A} X \rightarrow{ }_{Z-1}^{A} Y+e^{+}+\nu+Q_{2}\)
where,
mNXZA=Nuclear mass of XZA
mXZA=Atomic mass of XZA
mNYZ-1A=Nuclear mass of YZ-1A
mYZ-1A=Atomic mass of YZ-1A
me=Mass of an electron
c=Speed of light
Step 2: Find the Q-values for the two reactions.
Q-value of the electron capture reaction is given as:
Q1=mNXZA+me-mNYz-1Ac2
=mXZA-Zme+me-mYZ-1A+Z-1mec2
=mXZA- mYZ-1Ac2                                                       ...3
Q-value of the positron capture reaction is given as:
Q2=mNXZA+mNYz-1Ac2
=mXZA-Zme-mYZ-1A+Z-1me-mec2
=mXZA- mYZ-1A-2mec2                                                       ...4
Step 3: Compare the Q-values for the two reactions.
It can be inferred that if Q2>0, then Q1>0; Also, if Q1>0, it does not necessarily mean that Q2>0.
In other words, this means that if β+ emission is energetically allowed, then the electron capture process is necessarily allowed, but not vice-versa. This is because the Q-value must be positive for an energetically-allowed nuclear reaction.