Ncert Exercises & Solutions

3.6 A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6.0 × 10–7 m2, and its resistance is measured to be 5.0 Ω. What is the resistivity of the material at the temperature of the experiment?

Length of the wire, l = 15 m

Area of cross-section of the wire, a = 6.0 $\times$ 10^-7 m², Resistance of the material of the wire, R = 5.0 $Ω$ Resistivity of the material of the wire = $ρ$ , Resistance is related with the resistivity as

$R = ρ \frac{l}{A}$
$ρ = \frac{RA}{l}$
$= \frac{5 \times 6 \times 10^{- 7}}{15} = 2 \times 10^{- 7} Ω m$

Therefore, the resistivity of the material is $2 \times 10^{- 7} Ω m$ .

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