7.7 Phosphine
Preparation
NEETprep Audio Note:
Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3
Ca3P2 + 6HCl → 3CaCl2 + 2PH3
In the laboratory, it is prepared by heating white phosphorus with concentrated NaOH solution in an inert atmosphere of CO2.
When pure, it is non inflammable but becomes inflammable owing to the presence of P2H4 or P4 vapours. To purify it from the impurities, it is absorbed in HI to form phosphonium iodide (PH4I) which on treating with KOH gives off phosphine.
Properties
It is slightly soluble in water. The solution of PH3 in water decomposes in presence of light giving red phosphorus and H2. When absorbed in copper sulphate or mercuric chloride solution, the corresponding phosphides are obtained.
Phosphine is weakly basic and like ammonia, gives phosphonium compounds with acids e.g.,
In what way can it be proved that PH3 is basic in nature? NEETprep Audio Note:
Solution
Due to lone pair on phosphorus atom, PH3 is acting as a Lewis base in the above reaction.
Intext Questions
7.7 (a) Bond angle in PH4+ is higher than that in PH3. Why?
(b) What is formed when PH3 reacts with an acid?
7.8 What happens when white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO2 ?