6.6 Oxidation Reduction
NEETprep Audio Note:
2Cl–(aq) + 2H2O(l) → 2OH–(aq) + H2(g) + Cl2(g) (6.47)
The ∆GƟ for this reaction is + 422 kJ. When it is converted to EƟ (using ∆GƟ = – nEƟF), we get EƟ = – 2.2 V. Naturally, it will require an external emf that is greater than 2.2 V. But the electrolysis requires an excess potential to overcome some other hindering reactions (Unit–3, Section 3.5.1). Thus, Cl2 is obtained by electrolysis giving out H2 and aqueous NaOH as by-products. Electrolysis of molten NaCl is also carried out. But in that case, Na metal is produced and not NaOH.
4Au(s) + 8CN–(aq) + 2H2O(aq) + O2(g) → 4[Au(CN)2]–(aq) + 4OH–(aq) (6.48)
2[Au(CN)2]–(aq) + Zn(s) → 2Au(s) + [Zn(CN)4]2– (aq) (6.49)
In this reaction zinc acts as a reducing agent.