Heat
Work
Internal Energy & 1st Law of Thermodynamics
Calorimeter
6.3 Measurement of ∆U and ∆H: Calorimetry
We can measure energy changes associated with chemical or physical processes by an experimental technique called calorimetry. In calorimetry, the process is carried out in a vessel called calorimeter, which is immersed in a known volume of a liquid. Knowing the heat capacity of the liquid in which calorimeter is immersed and the heat capacity of calorimeter, it is possible to determine the heat evolved in the process by measuring temperature changes. Measurements are made under two different conditions:
i) at constant volume, qV
ii) at constant pressure, qp
(a) ∆U Measurements
NEETprep Audio Note:

(b) ∆H Measurements
NEETprep Audio Note:
In an exothermic reaction, heat is evolved, and system loses heat to the surroundings. Therefore, qp will be negative and ∆rH will also be negative. Similarly in an endothermic reaction, heat is absorbed, qp is positive and ∆rH will be positive.

Problem 6.6
1g of graphite is burnt in a bomb calorimeter in excess of oxygen at 298 K and 1 atmospheric pressure according to the equation
C (graphite) + O2 (g) → CO2 (g)
During the reaction, temperature rises from 298 K to 299 K. If the heat capacity of the bomb calorimeter is 20.7kJ/K, what is the enthalpy change for the above reaction at 298 K and 1 atm? NEETprep Audio Note:
Solution
Suppose q is the quantity of heat from the reaction mixture and CV is the heat capacity of the calorimeter, then the quantity of heat absorbed by the calorimeter.
q = CV × ∆T
Quantity of heat from the reaction will have the same magnitude but opposite sign because the heat lost by the system (reaction mixture) is equal to the heat gained by the calorimeter.
(Here, negative sign indicates the exothermic nature of the reaction)
Thus, ∆U for the combustion of the 1g of graphite = – 20.7 kJK–1
For combustion of 1 mol of graphite,
= – 2.48 ×102 kJ mol–1 , Since ∆ ng = 0,
∆ H = ∆ U = – 2.48 ×102 kJ mol–1