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The temperature coefficient of resistance of a wire is 2$\times <mspace\; width="1em"></mspace>{10}^{-5}<mspace\; width="1em"></mspace>°{\mathrm{C}}^{-1}$. If its temperature is increased by 200$°\mathrm{C}$, then the percentage increase in its resistance will be:
1.  2%
2.  0.2%
3.  4%
4.  0.4%
 

When the battery of emf V is applied across a conductor AB, the drift speed of electrons through the conductor is v. If the battery is replaced by a battery of emf $\frac{\mathrm{V}}{2}$, then the new drift speed of free electrons will be:

1.  v
2.  $\frac{\mathrm{v}}{2}$
3.  2v
4.  Zero

A current passes through a wire of variable cross-section in steady-state as shown. Then incorrect statement is:
  

The current in a wire varies with time according to the equation \(I=(4+2t),\) where \(I\) is in ampere and \(t\) is in seconds. The quantity of charge which has passed through a cross-section of the wire during the time \(t=2\) s to \(t=6\) s will be:

The length of a conductor is doubled keeping the volume constant. Percentage increase in its resistance is:
(1) 100%
(2) 200%
(3) 300%
(4) 400%

Which of the following graph represents the variation of resistivity ($\rho$) with temperature (\(T\)) for copper?

1.		2.
3.		4.

The colour code of resistance is given below:

The values of resistance and tolerance, respectively are:
1.  47 k$\mathrm{\Omega }$, 10%
2.  4.7 k$\mathrm{\Omega }$, 5%
3.  470 $\mathrm{\Omega }$, 5%
4.  470 k$\mathrm{\Omega }$, 5%

A carbon resistor of (47 ± 4.7) kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be:
1. Violet - Yellow - Orange - Silver
2. Yellow - Violet - Orange - Silver
3. Yellow - Green - Violet - Gold
4. Green - Orange - Violet - Gold

The smallest resistance that can be obtained by the combination of n resistors each of resistance R is:
1.  n²R
2.  nR
3.  $\frac{\mathrm{R}}{{\mathrm{n}}^2}$
4.  $\frac{\mathrm{R}}{\mathrm{n}}$

The resultant resistance value of n resistors, each of r ohms and connected in series is x. When those n resistors are connected in parallel, the resultant value is
1. $\frac{\mathrm{x}}{\mathrm{n}}$
2. $\frac{\mathrm{x}}{{\mathrm{n}}^2}$
3. ${\mathrm{n}}^2\mathrm{x}$
4. $\mathrm{nx}$

In the circuit shown in the figure, the effective resistance between A and B is:
                         
1.  2$\mathrm{\Omega }$
2.  4$\mathrm{\Omega }$
3.  6$\mathrm{\Omega }$
4.  8$\mathrm{\Omega }$

Find the equivalent resistance between A and E (the value of each resistor is R).

(1) $\frac{7}{12}\mathrm{R}$
(2) $\frac{7}{13}\mathrm{R}$
(3) $\frac{7}{15}\mathrm{R}$
(4) $\frac{8}{13}\mathrm{R}$

The figure below shows currents in a part of the electric circuit. The current \(i\) is:

The current I in the circuit shown below is:

1. $-3<mspace\; width="1em"></mspace>\mathrm{A}$
2. 3 A
3. 13 A
4. 20 A

What is the ratio of currents flowing in the resistors \(x\) and \(y\) of resistance \(10~\Omega\) each?
            
1. \(1\)
2. \(0.5\)
3. \(1.5\)
4. \(2.0\)

The total current  supplied to the circuit by the battery in the given circuit is:

1.  1 A
2.  2 A
3.  4 A
4.  6 A

The reading of an ideal voltmeter in the circuit shown is:

1. 0.6 V
2. 0 V
3. 0.5 V
4. 0.4 V

For the circuit given below, Kirchhoff's loop rule for the loop \(BCDEB\) is given by the equation:

As the switch S is closed in the circuit shown in the figure, the current passed through it is:

(1) 4.5 A
(2) 6.0 A
(3) 3.0 A
(4) Zero

Twelve wires of equal resistance \(R\) are connected to form a cube. The effective resistance between two diagonal ends \(A\) and \(E\) will be: