Please be patient as the PDF generation may take upto a minute.

The variation of pressure versus temperature of an ideal gas is shown in the given diagram. From this diagram, one can conclude that
 

A carnot engine having an efficiency of $\frac{1}{10}$th of heat engine, is used as a refrigerator. If then work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is:
1. 1 J
2. 90 J
3. 99 J
4. 100 J 

The temperature inside a refrigerator is ${t_2}^{\circ }C$and the room temperature is ${t_1}^{\circ }C$. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be:
1. $\frac{t_1}{t_1-t_2}$
2.  $\frac{t_1+273}{t_1-t_2}$
3. $\frac{t_2+273}{t_1+t_2}$
4.  $\frac{t_1+t_2}{t_1+273}$

The coefficient of performance of a refrigerator is 5. If the temperature inside freezer is -20°C, the temperature of the surroundings to which it rejects heat is  -
1. 31°C
2. 41°C
3. 11°C
4. 21°C

One mole of an ideal gas at an initial temperature of T K does 6R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of the gas will be:

An insulator container contains 4 moles of an ideal diatomic gas at temperature T. Heat Q is supplied to this gas, due to which 2 moles of the gas are dissociated into atoms but temperature of the gas remains constant. Then
1. Q = 2RT
2. Q = RT
3. Q = 3RT
4. Q = 4RT

P-V diagram of a diatomic gas is a straight line passing through origin. The molar heat capacity of the gas in the process will be -
1. 4 R
2. 2.5 R
3. 3 R
4. $\frac{4R}{3}$

The temperature-entropy diagram of a reversible engine cycle is given in the figure. Its efficiency is

1. 1/3
2. 2/3
3. 1/2
4. 1/4

When a system is taken from state i to a state f along path iaf, Q = 50 J and W = 20 J.
 If W = –13 J for the curved return path fi, Q for this path is -

1. 33 J
2. 23 J
3. – 7 J
4. – 43 J

An ideal gas is taken from point A to the point B, as shown in the P-V diagram. The work done in the process is -

1. $(P_A-P_B)(V_B-V_A)$
2. $\frac{1}{2}(P_B-P_A)(V_B+V_A)$
3. $\frac{1}{2}(P_B-P_A)(V_B-V_A)$
4. $\frac{1}{2}(P_B+P_A)(V_B-V_A)$

Thermodynamic processes are indicated in the following diagram: 

Match the following:  

One mole of an ideal monatomic gas undergoes a process described by the equation \(PV^3=\text{constant}.\) The heat capacity of the gas during this process is:
1. \(\frac{3}{2}R\)
2. \(\frac{5}{2}R\)
3. \(2R\)
4. \(R\)

The volume \((V)\) of a monatomic gas varies with its temperature \((T),\) as shown in the graph. The ratio of work done by the gas to the heat absorbed by it when it undergoes a change from state \(A\) to state \(B\) will be:
         

An engine has an efficiency of $\frac{1}{6}$. When the temperature of the sink is reduced by ${62}^{0}C$, its efficiency is doubled. the temperature of the source is:
1. 124^oC
2. 37^oC
3. 62^oC
4. 99^oC