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A wire has resistance 24 $\Omega$. It is bent in the form of a circle. The effective resistance between the two point on the diameter of the circle is 
(1) 6$\Omega$
(2) 4$\Omega$
(3) 3$\Omega$
(4) 12$\Omega$

The drift velocity of the electrons in a current-carrying  metallic conductor is of the order of 
1.  ${10}^4 \mathrm{m}/\mathrm{s}$
2.  ${10}^8 \mathrm{m}/\mathrm{s}$
3.  ${10}^0\mathrm{m}/\mathrm{s}$
4.  ${10}^{-4}\mathrm{m}/\mathrm{s}$

In the circuit shown in the figure, the effective resistance between A and B is:
                         
1.  2 $\mathrm{\Omega }$
2.  4 $\mathrm{\Omega }$
3.  6 $\mathrm{\Omega }$
4.  8 $\mathrm{\Omega }$

For the circuit shown in the figure, the value of R must be
                       
1.  3$\mathrm{\Omega }$
2.  4$\mathrm{\Omega }$
3.  5$\mathrm{\Omega }$
4.  6$\mathrm{\Omega }$

$\mathrm{In} \mathrm{the} \mathrm{circuit} \mathrm{shown} \mathrm{in} \mathrm{figure} \mathrm{if} \mathrm{power} \mathrm{dissipated} \mathrm{in} 9\mathrm{\Omega } \mathrm{resistor} \mathrm{is} 144\mathrm{W}, \mathrm{then} \mathrm{potential} \mathrm{difference} \mathrm{across} 3.6\mathrm{\Omega } \mathrm{resistor} \mathrm{will} \mathrm{be}$

1.  36V
2.  18V
3.  9V
4.  Zero

A battery has e.m.f. 4 V and internal resistance r. When this battery is connected to an external resistance of 2 ohm, a current of 1 ampere flows in the circuit. How much current will flow if the terminals of the battery are connected directly?

Three copper wires have their lengths in the ratio 5:3:1 and their masses are in the ratio 1:3:5. Their electrical resistance will be in the ratio of :
1. 5:3:1
2. 1:3:5
3. 125:15:1
4. 1:15:125

The current I as shown in the circuit will be:
                 
1.  10 A
2.  $\frac{20}{3}$ $\mathrm{A}$ $$
3.  $\frac{2}{3}$ $\mathrm{A}$ $$ $$
4.  $\frac{5}{3}$ $\mathrm{A}$

The current through the 5 $\mathrm{\Omega }$ resistor is:
 
1. 3.2 A                     
2. 2.8 A
3. 0.8 A                     
4. 0.2 A

The current in a wire varies with time according to the relation i= (3+2t) A. The amount of charge passing a cross section of the wire in the time interval t=0 to t=4.0 sec would be: (where t is time in seconds)

In the figure, a carbon resistor has bands of different colours on its body as shown. The value of the resistance is:
                                         
1.  2.2 k$\Omega$
2.  3.3 k$\Omega$
3.  5.6 k$\Omega$
4.  9.1 k$\Omega$

The resistivity of a wire :

The resistance of a wire is 10 Ω. Its length is increased by 10% by stretching. The new resistance will now be:
(1) 12.1 Ω
(2) 1.2 Ω
(3) 13 Ω
(4) 11 Ω

The potential difference between points A and B of the adjoining figure is

(1) $\frac{2}{3}V$
(2) $\frac{8}{9}V$
(3) $\frac{4}{3}V$
(4) 2 V

The reading of the ammeter as per figure shown is

(1) $\frac{1}{8}A$
(2) $\frac{3}{4}A$
(3) $\frac{1}{2}A$
(4) 2 A

In the figure shown, the total resistance between A and B is

(1) 12 Ω
(2) 4 Ω
(3) 6 Ω
(4) 8 Ω

A battery of e.m.f. 10 V is connected to resistance as shown in the figure below. The potential difference $V_A-V_B$  between the points A and B is:

1. –2 V
2. 2 V
3. 5 V
4. $\frac{20}{11}V$

What will be the equivalent resistance between the two points A and D 

(1) 10 Ω
(2) 20 Ω
(3) 30 Ω
(4) 40 Ω

The total current supplied to the circuit by the battery is:
      
1. 1 A
2. 2 A
3. 4 A
4. 6 A

In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to 3 volt. The voltage across the resistance R₄ is:

1. 0.4 V
2. 0.6 V
3. 1.2 V
4. 1.5 V