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(CH₃)₃CCI + (CH₃)₃C${\mathrm{O}}^{-}$ K⁺ → Product
1. S_N Product will be more
2. E₂ Product will be more
3. Both will be the same
4. None of the above

The correct statement regarding electrophile is

Which of the following is not correct for a nucleophile?
1. Nucleophile is a Lewis acid
2. Ammonia is a nucleophile
3. Nucleophiles attack low electron density sites
4. Nucleophiles are not electron seeking

A compound among the following that does not undergo Friedel-Craft's reaction easily is:
1. Cumene               
2.  Xylene
3. Nitrobenzene         
4. Toluene

Arrange the following compounds in increasing order of their reactivity toward electrophilic aromatic substitution reactions.

3-Phenylpropene on reaction with HBr gives (as a major product)-
1. $C_6{H}_{5}CH\left(Br\right)C{H}_2-C{H}_3$
2. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{CH}\left(\mathrm{Br}\right){\mathrm{CH}}_3$
3. ${\mathrm{C}}_6{\mathrm{H}}_4\left(\mathrm{Br}\right)<mspace\; width="1em"></mspace>{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CH}}_3$
4. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br}$

$\stackrel{\stackrel{\mathrm{H}}{|}}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{\stackrel{\mathrm{Cl}}{|}}{\mathrm{C}}{\mathrm{H}}_2\underset{\mathrm{alc}.}{\overset{\mathrm{NaOH}}{\to }}{\mathrm{CH}}_2={\mathrm{CH}}_2$
1. E1                                         
2. E2
3. $E{1}_{CB}$                                     
4. $\alpha$ elimination

For $S_{N}1$ reaction, the preferred solvent will be:

The main product of the following reaction will be-

1.		2.
3.		4.

The reaction of propene with HOCl proceeds via the addition of:

What results from the reaction of 2-bromopentane with alcoholic KOH?

What is the major product formed when toluene is refluxed with Br₂ in the presence of light?
1. p-Bromotoluene.
2. Benzyl bromide.
3. o-Bromotoluene.
4. Mixture of o- and p-bromotoluene.

The major product(s) in the below reaction is-
\(H_{3} C - CH = CH_{2} \xrightarrow[{\left(\right. Ph - CO - O \left.\right)_{2}}]{HBr} S\)
1. \(\underset{1 - Bromopropane}{H_{3} C - CH_{2} - CH_{2} Br}\)
2. \(\underset{2 - Bromopropane}{CH_{3} - \underset{Br}{\underset{\left|\right.}{CH}} - CH_{3}}\)
3. \(\underset{Propene}{CH_{3} - CH = CH_{2}}\)
4. None of the above

The type of radicals that can be formed as intermediates during monochlorination of 2-methylpropane is-
1. Primary and tertiary radicals
2. Two types of primary radicals
3. Primary and secondary radicals
4. Two types of tertiary radical

$\mathrm{Benzene}+{\mathrm{CH}}_3\mathrm{Cl}\stackrel{{\mathrm{AlCl}}_3}{\to }<mspace\; width="1em"></mspace>{\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_3$
The mechanism & intermediate involved in the above reaction are:
1. Aromatic electrophilic substitution & carbocation
2. Aromatic Nucleophilic substitution & carbanion
3. Aromatic free radical substitution & Free radical
4. Carbene based substitution reaction & Carbene

The correct representation involving heterolytic fission of ${\mathrm{CH}}_3-\mathrm{Br}$ among the following is:

1.
2.
3.
4.

The addition of HCl to an alkene proceeds in two steps. The first step is the attack of H⁺ ion on the double bond portion. The same can be shown as-

1.		2.
3.		4.	All of these are possible

Consider the reactions:

What products are formed when the following compound is treated with Br₂ in the presence of FeBr₃?
 

1.		2.
3.		4.

Chlorine atom can be classified as: