If the tension and diameter of a sonometer wire of fundamental frequency n are doubled and density is halved, then its fundamental frequency will become:
1.
2.
3. n
4.
Two waves have the following equations:
If in the resultant wave, the frequency and amplitude remain equal to the amplitude of superimposing waves, then the phase difference between them will be:
1.
2.
3.
4.
If the equation of a wave is represented by: \(y=10^{-4}~ \mathrm{sin}\left(100t-\dfrac{x}{10}\right)~\text m,\) where \(x \) is in meters and \(t\) in seconds, then the velocity of the wave will be:
1. | \(100\) m/s | 2. | \(4\) m/s |
3. | \(1000\) m/s | 4. | \(0\) m/s |
1. | \({y}=0.2 \sin \left[2 \pi\left(6{t}+\frac{x}{60}\right)\right]\) |
2. | \({y}=0.2 \sin \left[ \pi\left(6{t}+\frac{x}{60}\right)\right]\) |
3. | \({y}=0.2 \sin \left[2 \pi\left(6{t}-\frac{x}{60}\right)\right]\) |
4. | \(y=0.2 \sin \left[ \pi\left(6{t}-\frac{x}{60}\right)\right]\) |
The phase difference between two waves, represented by
\(y_1= 10^{-6}\sin \left\{100t+\left(\frac{x}{50}\right) +0.5\right\}~\text{m}\)
\(y_2= 10^{-6}\cos \left\{100t+\left(\frac{x}{50}\right) \right\}~\text{m}\)
where \(x\) is expressed in metres and \(t\) is expressed in seconds, is approximate:
1. \(2.07\) radians
2. \(0.5\) radians
3. \(1.5\) radians
4. \(1.07\) radians
1. | \(50~\text{cm}\) | 2. | \(60~\text{cm}\) |
3. | \(25~\text{cm}\) | 4. | \(20~\text{cm}\) |
1. | \(3\) | 2. | \(360\) |
3. | \(180\) | 4. | \(60\) |
The equations of two waves are given as x = acos(ωt + δ) and y = a cos (ωt + ), where δ = + /2, then the resultant wave can be represented by:
1. a circle (c.w)
2. a circle (a.c.w)
3. an ellipse (c.w)
4. an ellipse (a.c.w)